Smuggle PyCall and LaTeXStrings through PyPlot
fix #1672 fix https://github.com/JuliaPy/PyPlot.jl/issues/389 fix https://github.com/JuliaPy/PyPlot.jl/issues/408
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@ -526,8 +526,7 @@ const _plotlyjs_scale = _plotly_scale
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function _initialize_backend(::PyPlotBackend)
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@eval Main begin
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import PyPlot, PyCall
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import LaTeXStrings
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import PyPlot
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export PyPlot
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@ -539,11 +538,8 @@ end
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function add_backend_string(::PyPlotBackend)
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"""
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using Pkg
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Pkg.add("PyPlot")
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Pkg.add("PyCall")
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Pkg.add("LaTeXStrings")
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withenv("PYTHON" => "") do
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Pkg.build("PyCall")
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Pkg.add("PyPlot")
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Pkg.build("PyPlot")
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end
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"""
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@ -1,3 +1,6 @@
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# Do "using PyPlot: PyCall, LaTeXStrings" without dependency warning:
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const PyCall = PyPlot.PyCall
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const LaTeXStrings = PyPlot.LaTeXStrings
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# https://github.com/stevengj/PyPlot.jl
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@ -187,26 +190,22 @@ function add_pyfixedformatter(cbar, vals::AVec)
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cbar[:update_ticks]()
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end
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@require LaTeXStrings = "b964fa9f-0449-5b57-a5c2-d3ea65f4040f" begin
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function labelfunc(scale::Symbol, backend::PyPlotBackend)
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if scale == :log10
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x -> LaTeXStrings.latexstring("10^{$x}")
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elseif scale == :log2
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x -> LaTeXStrings.latexstring("2^{$x}")
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elseif scale == :ln
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x -> LaTeXStrings.latexstring("e^{$x}")
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else
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string
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end
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function labelfunc(scale::Symbol, backend::PyPlotBackend)
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if scale == :log10
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x -> LaTeXStrings.latexstring("10^{$x}")
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elseif scale == :log2
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x -> LaTeXStrings.latexstring("2^{$x}")
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elseif scale == :ln
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x -> LaTeXStrings.latexstring("e^{$x}")
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else
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string
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end
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end
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@require PyCall = "438e738f-606a-5dbb-bf0a-cddfbfd45ab0" begin
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function py_mask_nans(z)
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# pynp["ma"][:masked_invalid](z)))
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PyCall.pycall(pynp["ma"][:masked_invalid], Any, z)
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# pynp["ma"][:masked_where](pynp["isnan"](z),z)
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end
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function py_mask_nans(z)
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# pynp["ma"][:masked_invalid](z)))
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PyCall.pycall(pynp["ma"][:masked_invalid], Any, z)
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# pynp["ma"][:masked_where](pynp["isnan"](z),z)
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end
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# ---------------------------------------------------------------------------
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